Hardback £78 ISBN 0-19-926973-4
Paperback £25 ISBN 0-19-927041-4
A comprehensive philosophical introduction to set theory. Anyone wishing to work on the logical foundations of mathematics must understand set theory, which lies at its heart. I offer a thorough account of cardinal and ordinal arithmetic, and the various axiom candidates. I discuss in detail the project of set-theoretic reduction, which aims to interpret the rest of mathematics in terms of set theory. The key question here is how to deal with the paradoxes that bedevil set theory. I offer a strikingly simple version of the most widely accepted response to the paradoxes, which classifies sets by means of a hierarchy of levels. What makes the book unusual is that it interweaves a careful presentation of the technical material with a detailed philosophical critique: I do not merely expound the theory dogmatically but at every stage discuss in detail the reasons that can be offered for believing it to be true.
Contents
Part I: Sets
- Logic
- Collections
- The hierarchy
- The theory of sets
Part II: Numbers
- Arithmetic
- Counting
- Lines
- Real numbers
Part III: Cardinals and Ordinals
- Cardinals
- Basic cardinal arithmetic
- Ordinals
- Ordinal arithmetic
Part IV: Further Axioms
- Orders of infinity
- The axiom of choice
- Further cardinal arithmetic
Appendices
- Traditional axiomatizations
- Classes
- Sets and classes
Reviews
- Timothy Bays, Notre Dame Philosophical Reviews (2005)
- Stewart Shapiro, Mind 114 (2005) 764-7
- Arno Aurélio Viero, Manuscrito – Rev. Int. Fil. 28 (2005) 169-72
- Gabriel Uzquiano, Philosophia Mathematica 13 (2005) 308-46
- Elliott Mendelson, Zentralblatt 1066.03002
- Perry Smith, MR 2005d:03005
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Errata
p.44 l.14 For V ∪ V' read V ∩ V'.
p. 46 For the proof of proposition 3.6.13 substitute the following (thanks to Franz Fritsche):
Suppose that the proposition is false and V is the lowest level for which it fails, so that there is a history W of V such that W ≠ {V' : V' ∈ V}. Certainly V' ∈ W ⇒ V' ∈ V. So suppose now that V' ∉ W. Then for every V'' ∈ W we have V'' ≠ V' and V' ∉ V'' (since if V' ∈ V'' ∈ W then V' ∈ W), and so V'' ∈ V' [proposition 3.6.11]. So W ⊆ {V'' : V'' ∈ V'}, whence V = acc(W) ⊆ acc{V'' : V'' ∈ V'} = V' and therefore V' ∉ V (since otherwise V' ∈ V'). Contraposition gives V' ∈ V ⇒ V' ∈ W. Hence W = {V' : V' ∈ V}. Contradiction. ☐